A 10 Ω resistor carries 2 A. What is the power dissipated by the resistor?

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Multiple Choice

A 10 Ω resistor carries 2 A. What is the power dissipated by the resistor?

Explanation:
Power dissipated by a resistor comes from the current through it causing a voltage drop; this power can be calculated as P = I^2 R. With 2 A flowing through 10 Ω, P = (2 A)^2 × 10 Ω = 4 × 10 = 40 W. You can also find the voltage across the resistor using V = IR, which gives V = 2 A × 10 Ω = 20 V, and then P = VI = 20 V × 2 A = 40 W. So the resistor dissipates 40 watts.

Power dissipated by a resistor comes from the current through it causing a voltage drop; this power can be calculated as P = I^2 R. With 2 A flowing through 10 Ω, P = (2 A)^2 × 10 Ω = 4 × 10 = 40 W. You can also find the voltage across the resistor using V = IR, which gives V = 2 A × 10 Ω = 20 V, and then P = VI = 20 V × 2 A = 40 W. So the resistor dissipates 40 watts.

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