A capacitor has Q = 5 μC and V = 2 V. What is the capacitance?

A capacitor has Q = 5 μC and V = 2 V. What is the capacitance?

• A. 5 μF
• B. 1 μF
• C. 2.5 μF
• D. 10 μF

Answer: (C)

Capacitance relates stored charge to the voltage across the capacitor: C = Q / V. With Q = 5 μC and V = 2 V, C = 5 μC / 2 V = 2.5 μF. In standard units, 5 μC is 5×10^-6 C, so 5×10^-6 C divided by 2 V gives 2.5×10^-6 F, i.e., 2.5 μF. This also aligns with the idea that doubling the voltage (at the same capacitance) doubles the stored charge, since Q = C V.

Capacitance relates stored charge to the voltage across the capacitor: C = Q / V. With Q = 5 μC and V = 2 V, C = 5 μC / 2 V = 2.5 μF. In standard units, 5 μC is 5×10^-6 C, so 5×10^-6 C divided by 2 V gives 2.5×10^-6 F, i.e., 2.5 μF. This also aligns with the idea that doubling the voltage (at the same capacitance) doubles the stored charge, since Q = C V.