In a transformer with Np = 200 turns and Ns = 50 turns, if 120 V is applied to the primary, what is the secondary voltage?

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Multiple Choice

In a transformer with Np = 200 turns and Ns = 50 turns, if 120 V is applied to the primary, what is the secondary voltage?

Explanation:
In an ideal transformer, the output voltage scales with the turns ratio: Vs = Vp × (Ns/Np). Here, Ns/Np = 50/200 = 1/4. So the secondary voltage is 120 V × 1/4 = 30 V. The primary power is transferred to the secondary, so the secondary current rises by the inverse ratio (Is = Ip × Np/Ns). This is why a transformer with fewer turns on the secondary reduces the voltage proportionally.

In an ideal transformer, the output voltage scales with the turns ratio: Vs = Vp × (Ns/Np). Here, Ns/Np = 50/200 = 1/4. So the secondary voltage is 120 V × 1/4 = 30 V. The primary power is transferred to the secondary, so the secondary current rises by the inverse ratio (Is = Ip × Np/Ns). This is why a transformer with fewer turns on the secondary reduces the voltage proportionally.

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